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1.5x^2-7x-480=0
a = 1.5; b = -7; c = -480;
Δ = b2-4ac
Δ = -72-4·1.5·(-480)
Δ = 2929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{2929}}{2*1.5}=\frac{7-\sqrt{2929}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{2929}}{2*1.5}=\frac{7+\sqrt{2929}}{3} $
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